We will compare the implicit differentiation method from Calculus 1 and the "shortcut" from Calculus 3. We will find dy/dx of x^3+xy^2=sin(y). Subscribe to @bprpcalculusbasics for more calculus tutorials. Ask me calculus on Threads: @blackpenredpen ----------------------------- Support this channel and get my calculus notes on Patreon: 👉 Get the coolest math shirts from my Amazon store 👉 ----------------------------- #calculus #bprpcalculus #apcalculus #tutorial #math